12r^2+68r-16=8

Solution for 12r^2+68r-16=8 equation:

12r^2+68r-16=8

We move all terms to the left:

12r^2+68r-16-(8)=0

We add all the numbers together, and all the variables

12r^2+68r-24=0

a = 12; b = 68; c = -24;
Δ = b2-4ac
Δ = 682-4·12·(-24)
Δ = 5776
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5776}=76$
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(68)-76}{2*12}=\frac{-144}{24}
=-6
$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(68)+76}{2*12}=\frac{8}{24}
=1/3
$